air contains 20% O2
by volume. how many CC of air will be required for oxidation of 100 CC of acetylene.
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2C2H2+5O2⟶4CO2+2H2O2CX2HX2+5OX2⟶4COX2+2HX2O
From stoichiometric calculations:
2 C2H2CX2HX2 moles will react with 5 molecules of oxygen
1 C2H5⟶5/2CX2HX5⟶5/2 moles of O2OX2
22.4 l22.4 l C2H2⟶CX2HX2⟶ 5/2×22.4 l5/2×22.4 l of O2OX2
1 volume of air -> 0.2 (20/100) volume of oxygen
Now the only thing I don’t know is how to convert the volume into liters so that I can find the correct answer.
From stoichiometric calculations:
2 C2H2CX2HX2 moles will react with 5 molecules of oxygen
1 C2H5⟶5/2CX2HX5⟶5/2 moles of O2OX2
22.4 l22.4 l C2H2⟶CX2HX2⟶ 5/2×22.4 l5/2×22.4 l of O2OX2
1 volume of air -> 0.2 (20/100) volume of oxygen
Now the only thing I don’t know is how to convert the volume into liters so that I can find the correct answer.
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