Air contains 21% by volume of oxygen.
Find the volume of oxygen in a room of
dimensions 4 mx 5 mx 3 m.
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Answered by
1
Answer:
room dimensions 4×5×3 mtrs
60cube mtr
21/100% of 60 cube mtr
64/3
21.33 is oxygen
Answered by
6
Total volume of the room - (4 x 5 x 3)m^3 = 60 m^3
Therefore, volume of oxygen in the room - 21% of 60 m^3 = (21/100 x 60) m^3 = 12.6 m^3
Therefore, volume of oxygen in the room - 21% of 60 m^3 = (21/100 x 60) m^3 = 12.6 m^3
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