Find greatest number which 203 and 434 and leaving remainder 5 in each case
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Answered by
3
The numbers that are exactly divisible are
203 - 5 = 198
434 - 5 = 429.
Therefore the largest number which divides 203 and 434 leaving remainder 5
in each case = 33.
the nos exactly divisible are
203-5=198
434-5=429.
Answered by
2
Answer:
203-5=198
434-5 = 423
3)198,423
.............
11 ) 66. 143
---------------- ---..
6 I3
HCF=3x11=33
The greatest number is 33
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