Physics, asked by Anonymous, 1 year ago

air distance between kota to Jaipur is 260 km and road distance is 320 km . a deluxe bus which moves from Jaipur to kota takes 8 hours while an aeroplane reaches in just 15 min. Find:- a) average velocity of bus in km/hr b) average velocity of aeroplane in km/hr

Answers

Answered by nikkusing09876543
26
[1] avg. speed = 320 
                             8

[2] avg. velocity = total displacement 
                                  total time
     here displacement is 260 km as displacement is independent on path  so 260  = 32.5 km/h
                                                                                                                           8
for avg. velocity and avg speed of airplane apply above formula as displacement and distance covered are same for airplane so        
                      avg. speed of airplane = avg. velocity of airplane = 1040 km/h    

Anonymous: here displacement is 260 km as displacement is independent on path so 260 = 32.5 km/h ?????? Can you explain it please..........
Answered by kashyapnaik1234
1

Answer:

Explanation: average velocity= displacement/time

=260/8

32.5km/hr

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