pls do any 1 or both pls
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Q.no 7
answer is 2
hope it helps
answer is 2
hope it helps
rosy43:
im ain't getting properly could type or write and send
put the value 1
U 'll easily get it
but im not
idk to do properly pls help
1^3-6×1^2+7×1-4
1-6+7-4
-5+3
-2
ok
Answered by
1
7. Sub '1' for 'x'
1-6+7-4 = 8-10 = -2
8.
AB = BC
So, <B = <C
BD and CE being medians, BE = CD [since AB = AC and BE=1/2 AB && CD=1/2AC]
Now consider triangles CDB & BEC
BC = BC [common side]
BE = CD
<DCB = <EBC [angles of isosceles tria:<B=<C...included angle]
Hence the triangle CDB & BEC are congruent [Side-Angle-Side]
Hence BD = CE
So proved.
Hope it helps.
1-6+7-4 = 8-10 = -2
8.
AB = BC
So, <B = <C
BD and CE being medians, BE = CD [since AB = AC and BE=1/2 AB && CD=1/2AC]
Now consider triangles CDB & BEC
BC = BC [common side]
BE = CD
<DCB = <EBC [angles of isosceles tria:<B=<C...included angle]
Hence the triangle CDB & BEC are congruent [Side-Angle-Side]
Hence BD = CE
So proved.
Hope it helps.
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