air expands from 5 litres to 10 litres at 2 atm pressure. external work done is
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Answered by
68
Work W done is defined as integral of P dV for a gas
W = P (V2 - V1)
as pressure P is constant, where V2 = final volume and V1 = initial volume.
1 litre = 10⁻³ m³
W = 2 * 1.013 * 10⁵ N/m² (10 - 5) * 10⁻³ m³
= 1, 013 Joules
W = P (V2 - V1)
as pressure P is constant, where V2 = final volume and V1 = initial volume.
1 litre = 10⁻³ m³
W = 2 * 1.013 * 10⁵ N/m² (10 - 5) * 10⁻³ m³
= 1, 013 Joules
Answered by
7
Answer:
1000J is the correct answer
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