Math, asked by cutipieangliena31, 3 months ago

Air force is experimenting with three types of bombs P, Q and R in which three

kinds of explosives, viz. A, B and C will be used. Taking the various factors into

account, it has been decided to use at the maximum 600 kg of explosive A, at least 480

kg of explosive B and exactly 540 kg of explosive C. Bomb P requires 3, 2, 2kg, bomb

Q requires 1, 4, 3 kg and bomb R requires 4, 2, 3 kg of explosives A, B and C

respectively. Bomb P is estimated to give the equivalent of a 2 ton explosion, bomb Q,

a 3 ton explosion and bomb R, a 4 ton explosion respectively. Under what production

schedule can the Air Force make the biggest bang​

Answers

Answered by amitnrw
1

Given : Air force is experimenting with three types of bombs P, Q and R in which three  kinds of explosives, viz. A, B and C will be used.

Bomb P is estimated to give the equivalent of a 2 ton xplosion, bomb Q,  a 3 ton explosion and bomb R, a 4 ton explosion respectively.

To Find : Under what production  schedule can the Air Force make the biggest bang​

Solution:

Explosion = 2P + 3Q + 4R   to maximize

  3P + Q +   4R ≤ 600   Eq1

  2P + 4Q + 2R ≥ 480  Eq2

   2P + 3Q + 3R = 540   => 2P = 540 - 3Q - 3R

Substitute P in Eq1 and Eq2

=> 3(540 - 3Q - 3R)/2 + Q + 4R ≤ 600  

=> 1620 - 9Q - 9R + 2Q + 8R  ≤ 1200  

=>   7Q + R  ≥  420

 2P + 4Q + 2R ≥ 480

=> 540 - 3Q - 3R + 4Q + 2R ≥ 480

=>   R - Q  ≥ 60  => R  ≥ 60

                                                       Explosion = 2P + 3Q + 4R  

P = 45     Q = 45  ,   R = 105       90 + 135 + 420 = 645

P = 180    Q = 0  ,    R = 60         360 + 0 + 240  = 600

P = 0       Q = 60  ,   R = 120        0 + 180 + 480  = 660

Maximum is at  

P = 0       Q = 60  ,   R = 120

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