Chemistry, asked by ramnareshkumar, 11 months ago

Air is cooled from 273°C to 0°C. the decrease
in rms speed is about

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Answered by bhavmangal73
3

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Answered by abhi178
13

hence, decrease in rms speed by 23.23%

Air is cooled from 273°C to 0°C.

first of all, find rms speed at 273°C

temperature in Kelvin, T = 273 + 273 = 546 K

so rms speed , v_i = √{3R(546)/M} .....(1)

now find rms speed at 0°C

temperature in Kelvin, T = 0 + 273 = 273K

so, rms speed , v_f = √{3R(273)/M}.....(2)

now change in rms speeds , ∆v = v_f - v_i

= √{3R(273)/M} - √{3R(546)/M}

= √{3R/M} (√273 - √546)

= √{3R/M} (-6.8439)

= -6.8439 × √(3R/M)

now, % decrease in rms speed = change in speed/initial speed × 100

= [-6.8439 × √(3R/M)]/[√(3R(546)/M}] × 100

= -[684.39 × √(3R/M)]/[√546 × √(3R/M)]

= -684.39/23.36

= -29.29%

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