Air is cooled from 273°C to 0°C. the decrease
in rms speed is about
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Answer:
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Explanation:
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hence, decrease in rms speed by 23.23%
Air is cooled from 273°C to 0°C.
first of all, find rms speed at 273°C
temperature in Kelvin, T = 273 + 273 = 546 K
so rms speed , v_i = √{3R(546)/M} .....(1)
now find rms speed at 0°C
temperature in Kelvin, T = 0 + 273 = 273K
so, rms speed , v_f = √{3R(273)/M}.....(2)
now change in rms speeds , ∆v = v_f - v_i
= √{3R(273)/M} - √{3R(546)/M}
= √{3R/M} (√273 - √546)
= √{3R/M} (-6.8439)
= -6.8439 × √(3R/M)
now, % decrease in rms speed = change in speed/initial speed × 100
= [-6.8439 × √(3R/M)]/[√(3R(546)/M}] × 100
= -[684.39 × √(3R/M)]/[√546 × √(3R/M)]
= -684.39/23.36
= -29.29%
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