Question

Air is kept at a pressure of 200 kPa and a temperature of 30 °C in a 500 liters container. What is the mass of the air?

Answer 1

Answer:

1.2*10^6 kg

Explanation:

The molar mass of air is 28.9628 g/mol.

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Answer 2

The mass of air is 1.152 kg.

Air is kept at a pressure of 200 kPa and a temperature of 30°C in a 500 liters container.

We have to find the mass of the air.

Here given,

• Pressure, P = 200 kPa = 1.974 atm [ ∵ 1Pa = 9.87 × 10¯⁶ atm ]
• temperature, T = 30°C = 30 + 273 = 303K
• volume , V = 500 L
• universal gas constant, R = 0.082 atm.L/mol/K

using formula, PV = nRT

⇒1.974 × 500 = n × 0.082 × 303

⇒n = (1.974 × 500)/(0.082 × 303) = 39.725

we know, molecular weight of air, M = 29 g/mol

∴ mass of air = no of moles × molecular weight of air

⇒mass of air = 39.725 × 29 = 1152.025g ≈ 1.152 kg

Therefore the mass of air is 1.152 kg.