Ajar of height H is filled with transparent liquid of refractive index new at the centre of the jar on the bottom surface is a not find the minimum diameter of it is such that when it is placed on the top surface symmetrical about the centre the dot is invisible
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Your question seems to be incomplete. So you can find complete question through the attached document.
As the figure,we have to find a value for 'd'.
We can write [tex]tan(i) = (d/2)/h\\d/2 = h tan (i)\\d = 2h tan (i)------- (1)
Then we can use snell's law. Which is,
Refractive index of the medium X Sin value of the incident angle = constant
μ Sin(i) = 1 Sin (90)
μ Sin(i) = 1
Sin(i) = 1/μ----- (2)
Now we can get values for tan (i) by using above result.
tan (i) = 1/√(μ²-1) (see attached figure)
Substituting above value for equation (2),
d = 2h*1/√(μ²-1)
d = 2h/√(μ²-1)
Answer : d = 2h/√(μ²-1)
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