Math, asked by bhuvi7353, 7 months ago

Ajay and Vijay have 25 chocolates in total. If
Ajay gives 3 chocolates to Vijay, then the
number of chocolates with them is in the ratio
2:3 respectively. Find the number of chocolates
that Ajay and Vijay, had initially respectively.

Answers

Answered by Sanjalik20
1

Answer:

Ajay=7

Vijay=18

Step-by-step explanation:

let ajay has 2x chocolate and vijay =3x chocolate

ratio= 2:3

so 2x+3x=25

5x=25

x=5

ajay= 2*5=10

and vijay=3*5=15

ajay give 3chocolate to vijay now ajay have 7 chocolate and vijay have 18 chocolates

Hope it helps

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Answered by SuitableBoy
21

{\huge{\underline{\underline{\rm{Question-}}}}}

Q) Ajay and Vijay have 25 chocolates in total . If Ajay gives 3 choloates to Vijay , then the number of chocolates with them is in the ratio 2:3 respectively . Find the number of chocolates that Ajay and Vijay had initially .

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{\huge{\underbrace{\rm{Answer\checkmark}}}}

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Given :

# Initially , they both had 25 chocolates .

  • A + V = 25

# Now , Ajay gives 3 chocolates to Vijay

Ratio = 2:3

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To Find :

  • Chocolates they had initially .

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Solution :

Let Ajay has x chocolates initially

So ,

Chocolates Vijay had initially = 25 - x .

Now ,

Ajay gives 3 Chocolates to Vijay so ,

  • Chocolates Ajay has = x - 3
  • Chocolates Vijay has = 25 - x + 3 = 28 - x

According to Question :

 \rm \: chocolates \: ajay \: has  : chocoates \: vijay \: has = 2  : 3

 \mapsto \rm \: x - 3 : 28 - x = 2 : 3

 \mapsto \rm \:  \frac{x - 3}{28 - x} =  \frac{2}{3}  \\

 \mapsto \rm \: (x - 3)3 = (28 - x)2

 \mapsto \rm \: 3x - 9 = 56 - 2x

 \mapsto \rm \: 3x + 2x = 56 + 9

 \mapsto \rm \:  \cancel5x =  \cancel{65}

 \mapsto \pink{ \boxed{ \rm \: x = 13 \: }}

So ,

Initially

  • Ajay had = 13 Chocolates .
  • Vijay had = 25-13 = 12 Chocolates .

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