Question

ajay deposited 10000 rupees in a bank which compounds interest half-yearly at 10% annual rate.how much would he get back after 1 1/2 years?​

Answer 1

Answer:

Amount Ajay will get back Rs 11,576.25

Step-by-step explanation:

Principal (P) = Rs 10,000

Interest rate (r) = 10 %

Time (n) = 1 ½ year

To find:

Amount Ajay will get back

Solution :

⇒ $\sf{A \: = \: P \: (1 + \frac{r}{100} )^{n}}$

⇒ $\sf{A \: = \: 10000\: (1 + \dfrac{\frac{10}{2} }{100} )^{1.5 \times 2}}$

⇒ $\sf{A \: = \: 10000 \: (1 + 0.05)^{3}}$

⇒ $\sf{A \: = \: 10000 \: (1.05 )^{3}}$

A = 11,576.25

Therefore,

Amount Ajay will get back Rs 11,576.25

Answer 2

Question :-

• Ajay deposited 10000 rupees in a bank which compounds interest half-yearly at 10% annual rate.how much would he get back after 1 1/2 years?

Given :-

• Principal ( P ) = Rs, 10000
• Rate ( r ) = 10%
• Time ( n ) = 1 ½ years

To Find :-

• The Amount which Ajay will get back .

Solution :-

$\qquad \quad {:} \longrightarrow \sf \boxed{\bf{Amount \: = \: Principal \: \times \: \bigg(1 \: + \: \frac{Rate}{100} \bigg) ^{n} }}$

$\qquad \quad {:} \longrightarrow \sf {\sf{Amount \: = \: 10000 \: \times \: \bigg(1 \: + \: \frac{10}{100} \bigg) ^{1 \times \frac{1}{2} } }}$

$\qquad \quad {:} \longrightarrow \sf {\sf{Amount \: = \: 10000 \: \times \: \bigg(1 \: + \: \frac{10}{100} \bigg) ^{ \frac{3}{2} } }}$

$\qquad \quad {:} \longrightarrow \sf {\sf{Amount \: = \: 10000 \: \times \: \bigg(1 \: + \: \frac{ \frac{10}{2} }{100} \bigg) ^{ 3}} }$

$\qquad \quad {:} \longrightarrow \sf {\sf{Amount \: = \: 10000 \: \times \: \bigg(1 \: + \: \frac{ 5 }{100} \bigg) ^{ 3}} }$

$\qquad \quad {:} \longrightarrow \sf {\sf{Amount \: = \: 10000 \: \times \: \bigg(1 \: + \: 0.05 \bigg) ^{ 3}} }$

$\qquad \quad {:} \longrightarrow \sf {\sf{Amount \: = \: \bigg(10000 \: \times \: 1.05 \bigg) ^{ 3}} }$

$\qquad \quad {:} \longrightarrow \sf {\bf{Amount \: = \: Rs, 11576.25 }}$

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So, Ajay will get Rs, 11576.25 back after 1 ½ year.

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