ajay deposited 73000 rs in his account. he gave notes of denominations rs 10,rs50 and rs 100 inthe ratio 3:4:5 respectively, find the number of ratio of each denomination
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The number of ratio in each domination is
For domination 10 we have 3×100=300
Domination of 50=4×100=400
Domination of 100=5×100=500
Let the domination of each note be x
The value of 10 rupees is 3×10×x=30x
value of 50 rupees is 4×50×x=200x
value of 100 rupees is 5×100×x=500x
The total value is 73000
So we have,
30x+200x+500x=73000
730x=73000
Therefore x=100
So number of each notes
10 rupees note=3x=3×100=300
50 rupees note=4x=4×100=400
100 rupees note=5x=5×100=500
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