Question

Ajay gets 20% less marks than that of Vatsal 's marks. By what percent Vatsal's marks is more than Ajay's?
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Answer 1

Answer:

Answer : 25%

Step-by-step explanation:

If X is a% less than Y then

Y is (100a)/(100 - a) % greater rhan X

According to the given problem,

Let Ajay marks = x

Vatsal marks = y

Ajay gets 20% less marks than that of Vatsal's

here'a' = 20%

Required percentage = ( 100a)/(100 - a)

20)

= (100 x 20 ) / ( 100 - X

= ( 100 × 20)/80 X

= 25

Vatsal's marks is 25 % more than that of Ajay.

I hope this helps you.

Answer 2

Step-by-step explanation:

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CBSE

Mathematics

Grade 8

Percentage

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Ajay gets 20% less marks than that of Vatsal’s marks. By what percent Vatsal’s mark is more than Ajay’s marks?

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Hint: In this problem, first we need to find out the marks of Ajay and Vatsal in one variable. Next, find the percent increase in the mark of Vatsal. In percentage increase formula, we need to divide by Ajay’s marks instead of Vatsal’s marks because, here we need to find increase in Vatsal’s marks with respect to Ajay’s marks.

Complete step by step answer:

Let the mark of Vatsal’s be Rs.x.

Since, Ajay’s mark is 20% less than that of Vatsal, the mark of Ajay is calculated as follows:

Ajay'smarks=(100−20)%ofVatsal⇒Ajay'smarks=80100×x⇒Ajay'smarks=0.80x

Now, the percent increase in marks of Vatsal is calculated as follows:

Percent increase in marks of Vatsal = marks of Vatsal - marks of Ajaymarks of Ajay×100⇒Percent increase in marks of Vatsal = x−0.8x0.80x×100⇒Percent increase in marks of Vatsal = 0.2x0.80x×100⇒Percent increase in marks of Vatsal = 0.25×100⇒Percent increase in marks of Vatsal = 25

Thus, Vatsal’s marks is 25% more than