Math, asked by astha57, 1 year ago

ajay has built a cubical water tank and in his house. the top of the water tank is covered with lid. he wants to cover the inner surface of the tank including the lid with sq to tiles of sides 25cm. if each inner edge of the water tank is 2m long and tiles cost ₹360 per dozen, then find the total amount required for tiles.

Answers

Answered by gaganverma921167
16

Answer:

a of cube (a) 2m .. 2×100cm = 200cm

TSA of cube = 6a² = 6× 200 ×200cm²

Step-by-step explanation:

Area of s square sheet a square = 25 and 25 CM² square ..

No. of tiles = 384cm²

1 dozen 12 things

cost of 384 tiles = 384 × 30 = 11520cm²

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Answered by shilpa85475
10

The total amount required to line the tiles in Rs 11,520.

The shape of the water tank is cubical and the inner surface needs to tiled. Therefore, surface area of the cubical tank is supposed to be calculated.

Surface area of tank = 6 × area of each face

= 6 × 2²

= 24 sq. m

Number of tiles required to cover inner edge = surface area of tank / area of tile

= 24 / 0.25²

= 24 / 0.0625

= 384 tiles

Therefore, a total of 384 tiles are required to line the inner surface of the lid.

Amount of tiles required in dozens = number of tiles / 12

= 384 / 12

= 32 dozen

Total cost of lining = number of tiles in dozens × cost of a dozen tiles

= 32 × 260

= Rs 11,520

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