Math, asked by RITUPORNA8454, 1 year ago

Ajay invested certain amount in two different schemes A and B. Scheme A offers S.I. at 12% p.a. and scheme B offer C.I. at 10% p.a. Interest accrued on the amount invested in scheme A in 2 years was Rs. 3600 and the total amount invested was Rs. 35,000. What was the interest accrued on the amount invested in scheme B for 2 years?
(a) Rs. 4200
(b) Rs. 4400
(c) Rs. 4300
(d) Rs. 4100
(e) None of these

Answers

Answered by MaheswariS
4

Answer:

option (a) is correct

Step-by-step explanation:

concept:

1. simple interest formula:

simple\:interest=\frac{P\:n\:r}{100}


2. compound interest formula:\

compound \:interest= P(1+\frac{r}{100})^n-P



Let x and y be the amount invested in scheme A and scheme B respectively.


Then, x + y = 35000


Given:

simple interest accrued in 2 years = Rs. 3600

\frac{P\:n\:r}{100}=3600 \\\\\frac{(x)(2)(12)}{100}=3600 \\\\\frac{(x)(2)}{100}=300 \\\\\frac{x}{100}=150

x = Rs. 15000

y = 35000 - x

y = 35000 - 15000

y = Rs. 20000


compound interest accrued in 2 years

=P(1+\frac{r}{100})^n-P \\\\=20000(1+\frac{10}{100})^2-20000 \\\\=20000(1+\frac{1}{10})^2-20000 \\\\=20000(\frac{11}{10})^2-20000 \\\\=20000(\frac{121}{100})-20000

=200(121)-20000

= 24200 - 20000

=Rs. 4200

Answered by Anonymous
75

THE answer is :-

Rs. 4200

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