Ajay is older than his sister Anita by 12 years. 4 years ago, Ajay was four times as old as his sister. What are their present age? (Ajay and Anita) Explain with working.
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Take anita's age to be x
So, ajay's age would be x+12
Four yrs ago ajay's age would be = (x+12)-4 = x+8
Four yrs ago ajay was as old as anita's present age.( given)
=> x+8=x
=>2x=8
=>x=4
Thus, anita's age is 4 yrs.
and Ajay's age is 16 yrs.
So, ajay's age would be x+12
Four yrs ago ajay's age would be = (x+12)-4 = x+8
Four yrs ago ajay was as old as anita's present age.( given)
=> x+8=x
=>2x=8
=>x=4
Thus, anita's age is 4 yrs.
and Ajay's age is 16 yrs.
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