ajit carries a load of 17kg from the ground on his head and takes it to a height of 2m from the ground . calculate the work done
Answers
Answered by
6
m×g×h. so 17 ×10×2= 340 joule
Answered by
7
work done= force×displacement
=M×g×h
=17×10×2=340joules
=M×g×h
=17×10×2=340joules
Similar questions