Question

akash invested a sum of rupees 20000 at 10% percent per annum compound interest he gets an amount of rupees 24200 after n years find the value of n​

Answer 1

$\sf\large\underline{Given:}$

• $\rm{Invested\:sum=Rs.20000}$
• $\rm{Rate\:of\: Interest=10\%}$
• $\rm{Amount\:got=Rs.24200}$

$\sf\large\underline{To\: Find:}$

• $\rm{The\: value\:of\:(n)=?}$

$\sf\large\underline{Solution:}$

• To calculate the time we have to have apply the formula of amount:-]

$\sf\large\underline{Formula\:Used:}$

$\rm{\implies A=P[1+\dfrac{r}{100}]^n}$

• Here,
• P=Invested sum
• Time=n
• A=Amount

$\rm{\implies 24200=20000[1+\frac{10}{100}]^n}$

$\rm{\implies \dfrac{24200}{20000}=[\dfrac{110}{100}]^n}$

$\rm{\implies \dfrac{242}{200}=[\dfrac{11}{10}]^n}$

$\rm{\implies \dfrac{121}{100}=[\dfrac{11}{10}]^n}$

$\rm{\implies [\dfrac{11}{10}]^2=[\dfrac{11}{10}]^n}$

$\rm{\implies n=2}$

$\sf\large{Hence,}$

$\rm{\implies The\: value\:of\:n=2\:years}$

Answer 2

Step-by-step explanation:

clearly explain in pic