Question

Akhila went to a fair in her village. She wanted to enjoy rides on the Giant Wheel and play Hoopla (a game in which you throw a rig on the items kept in the stall, and if the ring covers any object completely you get it). The number of times she played Hoopla is half the number of rides she had on the Giant Wheel. Each ride costs Rs 3, and a game of Hoopla costs Rs 4. If she spent Rs 20 in the fair, represent this situation algebraically and graphically.​

Answer 1

Answer:

let no of giant wheel be x

let no of akhila took hoopla be y

no. of times she played hoopla=half of no.of rides she took

y=1 x

2

2y = x

2y- ×=0

Answer 2

Let no of times she had ride =x
There for hoopla will be = x/2

Total cost for all rides=3x
Total cost for hoopla =4x/2

By above information we can say
3x + 4x/2 = 20 ( ie is total amount spend in fair )

So 6x+4x/2 = 20
10 x = 40
X = 4
There fore no of rides = 4
No of hoopla games = 2

Cross check
Money spend on rides = 4 multiply by 3
= 12/-

Money spend on hoopla = 2 multiplied by 4 =8/-

Means total = 20/-