akita starts from rest and acceleration at 2 metre per second squared for 16 second calculate 8 the final velocity be the distance travelled
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It is said that, Akita starts from rest... It means that her initial velocity (u) =0
2) Her acceleration is 2m/sec squared for 16sec... It means that her acceleration was 2^2 =4 m/sec for 16 sec...
3) Therefore, it is asked that we gave to find the distance travelled... Which is equal to : d= acceleration * time
d= 4*16
d=64m
Then, it is asked to find the final velocity (v) : v= a+ut
v=a+ut
v= 4m/sec + 0*16
v= 4+0
v=4 m/sec
The final velocity is 4m/sec and distance travelled is 64 m
2) Her acceleration is 2m/sec squared for 16sec... It means that her acceleration was 2^2 =4 m/sec for 16 sec...
3) Therefore, it is asked that we gave to find the distance travelled... Which is equal to : d= acceleration * time
d= 4*16
d=64m
Then, it is asked to find the final velocity (v) : v= a+ut
v=a+ut
v= 4m/sec + 0*16
v= 4+0
v=4 m/sec
The final velocity is 4m/sec and distance travelled is 64 m
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