Question

Akram is twice as old as shazia. five years ago his age was three times shazia age. find their present ages..

plz help me out this!! ​

Answer 1

Answer:

Answer

let age of Akram be

′

x

′

and age of Shazia be

′

y

′

then according to question x=2y−−−(1)

and five years ago

x−5=3(y−5)

x−5=3y−15

x−3y+10=0−−−(2)

using eq(1)

2y−3y+10=0

y=10

and x=20

∴ age of Akram is 20 and age of Shazia is 10