Akshay and Tina have overweight so their family doctor advised them to go for morning walk daily. Akshay takes two rounds of a square park of side 140 m and Tina takes 3 rounds of rectangular park of length 70 m and breadth 45 m. Find who covers more distance and by how much. What value is depicted by Akshay and Tina?
Answers
Answer:
In one round, Mohit covers a distance equal to perimeter of rectangle =2(length+breadth)=2(80+40)
=240m
⇒ In five rounds, he covers =240×5=1200m
=1.2km.
Anju is health conscious.
Step-by-step explanation:
In one round, Mohit covers a distance equal to perimeter of rectangle =2(length+breadth)=2(80+40)
=240m
⇒ In five rounds, he covers =240×5=1200m
=1.2km.
Anju is health conscious.
Answer:
Akshay by 430 m
Step-by-step explanation:
Perimeter of a square = length of the side multiplied by 4
Perimter of the square park = 140m * 4
560m
Distance walked by Akshay if he takes 2 rounds = 560m * 2
560m * 2 = 1120m
Perimeter of a rectangle = 2(l+b)
Perimter of the rectangular park= 2(70m + 45m)
2(115)m
2 * 115 m = 230m
Distance walked by tina if she takes 3 rounds of the rectangular park = 230m * 3
230m * 3 = 690m
1120m - 690m = 430 meters
Hence Akshay walked more distance than tina by 430m