Math, asked by sdmenkudale2019, 7 months ago

Akshu can do a piece of work in
10 days and Harshal can do same work in
12 days. They started working together but
Akshu left the work 2 days before
completion of work, then how much time
taken to complete the work?​

Answers

Answered by amitnrw
5

Given : Akshu can do a piece of work in  10 days and Harshal can do same work in  12 days.

They started working together but  Akshu left the work 2 days before

completion of work

To Find : how much time  taken to complete the work?​

Solution:

Akshu can do a piece of work in  10 days

Akshu 1 day work = 1/10

Harshal can do a piece of work in  12 days

Harshal 1 day work = 1/12

Their 1 day work = 1/10 + 1/12  =  11/60

Their n days work = n * 11/60

Last 2 Days work by Harshal = 2 (1/12)  = 1/6

Remaining work done by both = 1 - 1/6   = 5/6

n * 11/60  = 5/6

=> n = 50/11

=> n =  4.545  

Total time Taken = 4.545 + 2 = 6.545 Days

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Answered by khush522738
2

Step-by-step explanation:

here , x= 10

y= 12

t= 2

complete the work = ( x+t)y/(x+y)

= ( 10+2)12/ (10+12)

=12×12/22

= 144/22

= 6 6/11

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