Math, asked by prabhumelvin2005, 1 month ago

al bucket is in the shape of a frustum of a cone.mounted on a hollow cylindrical base made of the same metallic sheet.The diameters of the two circular ends of the bucket are 45cm and 25cm the total vertical height of the bucket is 40cm and that of the cylindrical base is 6cm .Find the area of the metallic sheet used to make the bucket where we do not take into account the handle of the bucket.Also tind the volume of water the bucket can hold.( Take Pi=(22)/(7) ).​

Answers

Answered by sainathfulmanthe
0

Answer:

The total height of the bucket = 40 cm, which includes the height of the base. So, the height of the frustum of the cone = (40 – 6) cm = 34 cm. The area of metallic sheet used = curved surface area of frustum of cone + area of circular base + curved surface area of cylinder Now the volume of water that the bucket can hold (also, known as the capacity of the bucket) Read more on Sarthaks.com - https://www.sarthaks.com/32972/open-metal-bucket-shape-frustum-cone-mounted-hollow-cylindrical-base-same-metallic-sheet

hope this is help you☺ friend

Similar questions