Question

al. Expand the following using the identies
(8ab –2cd )2​

Answer 1

Answer:

(a-b)^2

Step-by-step explanation:

64ab^2-32abcd+4cd

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Answer 2

$\sf{Answer}$

Step by step explanation:-

It is in form of (a-b)² = a²-2ab + b²

So,

(8ab -2cd)² = (8ab)² -2 (8ab) ( 2cd) + (2cd)²

(8ab-2cd)² = 8²×a²×b² -2 × 8 × ab × 2×cd + 2² ×c²×d²

(8ab -2cd)² = 64a²b² -32abcd + 4c²d²

So, (8ab-2cd)² = 64a²b² -32abcd +4c²d²

Know more algebraic identities

( a +b)² = a²+b²+2ab

(a + b) ( a -b) = a²-b²

(a+b)³ = a³+b³ +3ab (a +b)

(a -b)³ = a³ -b³ -3ab(a-b)

a³ + b³ = (a +b) ( a²-ab + b²)

a³-b³ = (a-b) (a²+ab+b²)

(a + b+ c)² = a² + b² +c²+2ab+2bc+2ca

Hope u helpful :)