Al2(SO4)3+6NaOH_2Al(IH)3+3Na2SO4
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HEY MATE HERE IS YOUR ANSWER :
Al2(SO4)3 + 6NaOH —> 2Al ( OH ) 3 +3Na2So4
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Al2(SO4)3 (aq) + 6 NaOH (aq) → 2 Al(OH)3 (s) + 3 Na2SO4 (aq)
This is a precipitation reaction: Al(OH)3 is the formed precipitate.
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