Al2(SO4)3+6NaOH_2Al(IH)3+3Na2SO4
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Explanation:
Since aluminium sulphate is in excess, it implies that sodium hydroxide is the limiting reactant and decides how much product is formed as it gets used up first.
The balanced chemical equation represents the mole ratio in which the chemicals react.
Since 6molNaOH produces 2molAl(OH)3, ie 3 times less, it implies that 2,3 moles of NaOH will produce 2.33=0.767 moles of Al(OH)3.
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