Question

albert can finish a task in 12 days while bill takes 15 days to finish the task. if albert, bill, and charles working together can finish the task in 6 days, c alone can finish the task in

Answer 1

1÷12 + 1÷15 +1÷c = 1÷6
C=60 days

Answer 2

If Albert, Bill, and Charles can together finish the task in 6 days, then Charles alone can finish the task in 60 days.

Step-by-step explanation:

Albert can finish a task in = 12 days

So, work done by Albert in 1 day = $\frac{1}{12}$

Bill can finish a task in = 15 days

So, work done by Bill in 1 day = $\frac{1}{15}$

Albert, Bill & Charles together can finish the task in = 6 days

So, work done by (Albert + Bill + Charles) in 1 day = $\frac{1}{6}$

Therefore,

The work done by Charles in 1 day is given by,

= [Work done by (Albert + Bill + Charles) in 1 day] – [Work done by (Albert + Bill) in 1 day]

= $\frac{1}{6} - [\frac{1}{12} + \frac{1}{15} ]$

= $\frac{1}{6} - \frac{1}{12} - \frac{1}{15}$

= $\frac{10 - 5 -4}{60}$

= $\frac{1}{60}$

Thus, Charles alone can finish the task in 60 days.

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