Algebra 9th std
please help and show working or explanation (see attachment) answer is marked but how the answer came I want explanation or working
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mean of x1, x2, x3, .....xn, y1, y2, y3 ,.... yn will be sum of all this numbers devided by total numer
= (x1+x2+....+xn + y1+y2+...+yn)/(n+n)
= (x1+x2+....+xn + y1+y2+...+yn)/(2n)
=(1/2) (x1+x2+....+xn + y1+y2+...+yn)/(n)
= (1/2)((x1+x2+....+xn)/n + (y1+y2+...+yn)/n)
= (1/2)(x'+y' )
= (x1+x2+....+xn + y1+y2+...+yn)/(n+n)
= (x1+x2+....+xn + y1+y2+...+yn)/(2n)
=(1/2) (x1+x2+....+xn + y1+y2+...+yn)/(n)
= (1/2)((x1+x2+....+xn)/n + (y1+y2+...+yn)/n)
= (1/2)(x'+y' )
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