algebra equations class6
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Question:
Find the number if 18 is taken away from the 6 times of a number is 30.
Solution:
Let ‘a ‘ be the number.
Given: 18 is taken away from the 6 times of a number is 30.
6a – 18 = 30
6a = 30 + 18
6a = 48
a=48 / 6
a=8
Therefore, the number is 8.
Question 2:
Solve the equation given below and find the value of x and y
x + y = 3
x – y = 1
Solution:
Given,
x + y = 3 …(1)
x – y = 1 …..(2)
By solving two equations, we get
2x = 4
X = 4/2
x= 2
Substitute x= 2 in equation (1), we get
2 + y =3
y = 3 – 2
y = 1
Therefore, x = 2 and y =1
Step-by-step explanation:
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