algebra question 3a - 4b
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4b-3a
4+3=7
a+b=1
7+1=8
hence,3a-4b=8b
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Given, (3a−4b).
On squaring, we get, (3a−4b)² .
We know, (x+y)² =x ² +y ² +2xy.
Then,
(3a−4b)²
=(3a)² −2(3a)(4b)+(4b)²
=9a² −24ab+16b² .
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