Question

algebraic expressions for a number multiplied by itself and then with another number​

Answer 1

Answer:

let one number be 'x'.

when 'x' is multiplied by itself we get $x^{2}$

let the other number be 'y'.

by multiplying  $x^{2}$ with 'y' we get $x^{2} y$

hence x^2 y [$x^{2} y$] is the required answer.