Question

algebraic identities expand the following (4x+y-3z)^2​

Answer 1

Answer:

(4x−2y−3z)

2

We know that (x+y+z)

2

=x

2

+y

2

+z

2

+2xy+2yz+2xz

Here x=4x, y=-2y and z=-3z we get

(4x−2y−3z)

2

=(4x)

2

+(−2y)

2

+(−3z)

2

+2(4x)(−2y)+2(−2y)(−3z)+2(4x)(−3z)

=16x

2

+4y

2

+9z

2

−16xy+12xy−24xz

Answer 2

Answer:

$(4x+y-3z)^2 \\ \\ = {(4x)}^{2} + ( {y)}^{2} + {( - 3z)}^{2} + 2 \times 4x \times y + 2 \times y \times ( - 3z) + 2 \times ( - 3z) \times 4x \\ \\ =16 {x}^{2} + {y}^{2} + 9 {z}^{2} + 8xy - 6yz - 24xz \\ \\ this \: is \: ur \: required \: answer \: :):):):):)$