Question

prove that 2-root 7is irrational,root7is irrational​

Answer 1

Step-by-step explanation:

let assume that root 7 is a rational

$2 - \sqrt{7}$

here q is not equal to 0

(p,q)=1

$2 - \sqrt{7} = \binom{p}{q} \\ 2 - \binom{p}{q} = \sqrt{7}$

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2q-p/q=/7

here 2q-p/q Is a rational number.

and root 7 is irrational number

So it is not possible. So it is a irrational number