Question

Alice has worked 8 years longer than Kathy . Kathy has worked half as long as Sheila. If Sheila has worked at the company for 10 years, How many years has Alice worked there

Answer 1

Given :-

• Number of years Shiela has worked = 10 years
• Number of years Kathy has worked = Half as of Shiela
• Number of years Alice has worked = 8 more than Kathy

According to the question :-

Number of years Kathy has worked

$= > \frac{number \: of \: years \: shiela \: has \: worked}{2} \\ = > \frac{10}{2} = 5 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Number of years Alice has worked,

=> 8 more than Kathy

=> 5 + 8 = 13 years

Therefore :-

• Nunber of years Kathy worked is 5 years.
• Number of years Alice has worked is 13 years.

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Hope it helps you mate :)

Answer 2

Answer:

Alice worked 13 Years

Step-by-step explanation:

If Sheila worked for 10 years

Then Kath has worked for 5 years (half of 10 years)

Finally Alice has worked for 5+8 = 13 years