Question

alift is designed to carry a load of 4000kg through 10 floors of building. averaging 6m per floor in 10s cal. the power of lift​

Answer 1

Refer to attachment....

Answer 2

Answer:

Explanation:

height =10 * 6 => 60m

mass = 4000kg and let g = 10m/s^2

therefore , force => mg => 4000*10=> 400000N

so work done => force * displacement

=> 40000*60 => 2400000J

time taken => 10 sec

therefore power => 2400000/10 => 240000W

therefore horse power => 240000/746

=> 321.7 J