Question

all 5 plz answer i will mark you as brainliest

Answer 1

2) according to euclids division lemma
a=bq+r (1)
Here
b=53
q=34
r=2
Apply in (1)
We get a =53×34+2
a=1804

3)4^n=(2×2)^n
The prime factorisation of 4 is 2 and 2.By fundamental theorem of arithmetics guarantees that there is no other primes in the factorisation of 4^n.So there is no natural number n for which 4^nends with 0.

4)Given remainder is 8.first step is to divide remainder from given nos.
First no =248-8
=240
Second no =1032-8=1024
Now find hcf of 240 and 1024
1024=240×4+64
240=64×3+48
64=48×1+16
48=16×3+0
That is hcf=16
5)ans =2
Hope it helps you.i don t know ans of 1 ques.MARK AS BRAINLIEST