Physics, asked by kunichanpradeep1903, 8 months ago

All electrons ejected from a surface by incident light of
wavelength 200nm can be stopped before travelling 1m in
the direction of uniform electric field of 4N/C. The work
function of the surface is
(a) 4 eV (b) 6.2 eV (c) 2 eV (d) 2.2 eV

Answers

Answered by Anonymous

Answer:

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Answered by sampakrish123

Answer:

Hey mate,

The question is incomplete. Complete question is attached with image.

● Answer-

φ = 2.2 eV

● Explaination-

# Given-

E = 4 N/C

d = 1 m

λ = 200 nm = 2×10^-7 m

# Solution-

Here, kinetic energy provided gets converted to electric field energy.

1/2 mv^2 = Ede

1/2 mv^2 = 4 × 1 × e

1/2 mv^2 = 4 eV

Incident photon emits energy-

hυ = 12.4×10^-9 / 2×10^-9

hυ = 6.2 eV

Work function of the surface is-

φ = hυ - 1/2 mv^2

φ = 6.2 - 4

φ = 2.2 eV

Work function of the surface is 2.2 eV .

Hope this is useful...

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