Question

ALL IDENTITIES POLYNOMIALS CH-2., EX-2.5 Class 9th

Answer 1

Answer:

(a+b)²= (a)²+2ab+(b)²

(a-b)²=(a)²-2ab+b²

a²-b²=(a+b)(a-b)

(x+a)(x+b)= x²+(a+b)x+ab

(a+b+c)²=a²+b²+c²+2ab+2bc+2ac

(a+b)³=(a)³+(b)³+3ab(a+b)

(a-b)³=(a)³=(b)³-3ab(a-b)

a³+b³=(a+b)(a²-ab+b²)

a³-b³=(a-b)(a²+ab+b²)

a³+b³+c³-3abc= (a+b+c)(a²+b²+c²-ab-bc-ac)

x³+y³+z³=3xyz if x+y+z=0