Question

all of you know that quadratic Equations have 2 roots...... then find the 2 roots of this quadratic Equation-. (x+1)(x+1)=2(x-3)

Answer 1

↑ Here is your answer ↓
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Multiply first,

$(x+1)(x+1) = 2(x-3)$

$x(x+1) + 1(x+1) = 2x-6$

$x^2 + x + x + 1 = 2x - 6$

$x^2 + 2x + 1 = 2x - 6$

Lets open now,

$x^2 + 2x + 1 - 2x + 6 = 0$

$x^2 + 7 = 0$

$x^2 = -7$

$x = \sqrt{-7}$