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13) As AOB is a straight line , x+(x+10°)+(x+20°)=180°=> 3x+30°=180°=> 3x=180°-30°=150°=>
x=150°/3=50°. (3)is the correct option.
14) As AOB is a straight line,3x+3x=180°=> 6x=180°=>x=30°. (3) is the correct option.
15) let angle POS and angle ROS be 4k and 5k as POQ is a straight line=> 4k+5k=180°=> 9k=180°=> k=20°. angle SOQ =angle ROQ + angle ROS =90°+5(10°)=140°. (4)is the correct option.
x=150°/3=50°. (3)is the correct option.
14) As AOB is a straight line,3x+3x=180°=> 6x=180°=>x=30°. (3) is the correct option.
15) let angle POS and angle ROS be 4k and 5k as POQ is a straight line=> 4k+5k=180°=> 9k=180°=> k=20°. angle SOQ =angle ROQ + angle ROS =90°+5(10°)=140°. (4)is the correct option.
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