All sides of a quadrilateral ABCD touch a
circle. If AB = 6 cm, BC = 7.5 cm, CD = 3 cm,
then DA is
A) 3.5 cm B) 4.5 cm C) 2.5 cm D) 1.5 cm
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Answer:
D) 1.5 cm
Step-by-step explanation:
as tangents drawn from external point are equal
AE=AH....i
BE=BF......ii
GC=FC....iii
GD=HD....iV
Adding i,ii,iii & IV
AE+BE+GC+GD = AH+BF+FC+HD
AB+CD = AD+BC
6+3 = AD +7.5
AD= 9-7.5= 1.5CM
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