Question

All telephone numbers have 6 digits first 2 digits always being 41 or 42 or 46 or 62 or 64 thr numbers having all 6 digit are

Answer 1

Step-by-step explanation:

If first two digit is 41, the remaining 4 digits can be arranged in 8P4 = 8 x 7 x 6×5 = 1680 ways.

If first two digit is 41, the remaining 4 digits can be arranged in 8P4 = 8 x 7 x 6×5 = 1680 ways.Similarly, if first two digit is 42, 46, 62, or 64, the remaining 4 digits can be arranged in 8P4 ways i.e., 1680 ways.

If first two digit is 41, the remaining 4 digits can be arranged in 8P4 = 8 x 7 x 6×5 = 1680 ways.Similarly, if first two digit is 42, 46, 62, or 64, the remaining 4 digits can be arranged in 8P4 ways i.e., 1680 ways..’. Total number of telephone numbers having all six digits distinct = 5x 1680 = 8400

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Answer 2

Answer:

If first two digit is 41, the remaining 4 digits can be arranged in 8P4 = 8 x 7 x 6 × 5 = 1680 ways. Similarly, if first two digit is 42, 46, 62, or 64, the remaining 4 digits can be arranged in 8P4 ways i.e., 1680 ways. .’. Total number of telephone numbers having all six digits distinct = 5 x 1680 = 8400Read more on Sarthaks.com - https://www.sarthaks.com/128164/certain-city-all-telephone-numbers-have-six-digits-the-first-two-digits-always-being-46-or