Question

All the exterior angles of a pentagon is x x+20 x+40 x+60 x+80 find the value of smallest angle

Answer 1

Answer:

Step-by-step explanation:

Sum of the angles of a pentagon = 540°°

Thus,

x+(x+20)+(x+40)+(x+60)+(x+80)=540°⇒5x+200= 540°⇒5x=340°⇒x=3405⇒x=68°x+x+20+x+40+x+60+x+80=540°⇒5x+200= 540°⇒5x=340°⇒x=3405⇒x=68°

Thus, the smallest angle is 68°°.