Question

All the oxygen in 0.5434 g sample of pure oxide of iron is removed by reduction in a stream of H2. the loss in weight is 0.1210 g. what is the formula of the oxide of iron ?

Answer 1

Answer:

Formula for oxide of iron is FeO

Explanation:

weight of iron oxide=0.5434g

weight of oxygen lost as H2O=0.1210g

Then the weight of iron=0.5434-0.1210=0.4224g

Element           Amount             %                      Mole Ratio

Iron                  0.4224g       77.731.39                       1

Oxygen           0.1210g         22.261.39                      1

So the formula is FeO