Question

all the questions......
who answers all questions will be marked as brainliest
pls..answer faster

Answer 1

Answer no. 6.......................
Find the distance for each section of the journey:
60*0.52=31.2km
30*0.24=7.2km
70*0.71=49.7km
The total distance travelled=31.2+7.2+49.7km=88.1km
The total time=0.52+0.24+0.71h=1.47h
The average speed=distance/time 88.1/1.47=59.9kmph
Answer no. 7......................
Speed of the train in the first 30km,v1=30km/h
Speed of the train in the next 90km,v2
Average speed=60km/h=(v1+v2) /2
(30km/h+v2) /2
V2=90km/h
Answer no. 8..........................
Distance=200km
Time=5h
Speed=distance/time
Speed=200/5=40km/h
Velocity=displacement/time
But there is no displacement, so, displacement=distance
Therefore, Velocity=40km/h
Answer no. 9.......................
Average speed= (speed1+speed2)/2
Speed1=250/5=50m/s
Speed2=250/5=50m/s
Average speed=(50+50)/2=50m/s
Average velocity=0 because the displacements is 0 as the bus come back to Delhi covering the same distance.