All the red face cards are removed from a pack of 52 playing cards. A card is drawn at random from the remaining cards, after reshuffling them. Find the probability that the drawn card is
(i) of red colour
(ii) a queen
(iii) an ace
(iv) a face card
Answers
Answered by
3
1) p ( e) = 10 / 49
2) p(e) = 3 / 49
3) p( e) = 4 /49
4) p( e) = 9 /49
Hope it helps you
tanishq972003:
wrong
Answered by
12
HEY MATE,
THEIR ARE 52 CARDS AND ALL RED FACE CARDS ARE REMOVED.
SO NO. OF REMAINING CARDS = 52 - 6
= 46.
1) THEIR ARE 46 CARDS REMAINING AND OF RED COLOUR AS 6 CARDS ARE REMOVED FROM RED COLOUR CARDS SO = 26 - 6
= 20
P(RED COLOUR) = 20/46
= 10/23.
2) TWO QUEENS ALREADY REMOVED SO 4-2= 2
P(QUEEN)= 2/46 = 1/23.
3) THEIR ARE 4 ACE IN CARDS SO
P(ACE)= 4/46 = 2/23
4) THEIR ARE TOTAL 12 FACE CARD IN WHICH 6 ARE REMOVED SO = 12-6= 6
P(A FACE CARDS) = 6/46
= 3/23.
I HOPE THIS WILL HELP YOU...
PLS MARK AS BRAINLIEST.
THEIR ARE 52 CARDS AND ALL RED FACE CARDS ARE REMOVED.
SO NO. OF REMAINING CARDS = 52 - 6
= 46.
1) THEIR ARE 46 CARDS REMAINING AND OF RED COLOUR AS 6 CARDS ARE REMOVED FROM RED COLOUR CARDS SO = 26 - 6
= 20
P(RED COLOUR) = 20/46
= 10/23.
2) TWO QUEENS ALREADY REMOVED SO 4-2= 2
P(QUEEN)= 2/46 = 1/23.
3) THEIR ARE 4 ACE IN CARDS SO
P(ACE)= 4/46 = 2/23
4) THEIR ARE TOTAL 12 FACE CARD IN WHICH 6 ARE REMOVED SO = 12-6= 6
P(A FACE CARDS) = 6/46
= 3/23.
I HOPE THIS WILL HELP YOU...
PLS MARK AS BRAINLIEST.
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