Question

Allele frequencies of homozygous is 0.64 what will be the frequency of heterozygote

Answer 1

AA = p² (for the AA homozygotes)

aa = q² (for the aa homozygotes)

Aa = 2pq (for the Aa heterozygotes)

As, p2+ 2pq +q2 = 1

As per ur question

p^2=0.64. p=0.8

And p+q =1

0.8+q =1 so, q=0.2

Therefore, heterozygotes =2pq=2×0.8×0.2=0.32.

Hope this will help u