Question

ALLEN
(102) The enthalpy of vapourisation of liquid water using
the data:
Hg)+ 0,0 H20 (0); AH =-285.77 kJmol
1/20
1
H g) + 5 020) — H2O(g); AH=-241.84 kJ/mol
(1) + 43.93 kJ/mol
(3) + 527.61 kJ/mol
(2) - 43.93 kJ/mol
(4) - 527.61 kJ/mol

i want quick solution​

Answer 1

Answer:

The thermochemical reactions are as given below.

H

2

(g)+

2

1

O

2

(g)→H

2

O(l);ΔH=−285.77KJmol

−1

......(1)

H

2

(g)+

2

1

O

2

(g)→H

2

O(g);ΔH=−241.84KJmol

−1

......(2)

The reaction (1) is reversed and added to the reaction (2) to obtain the reaction for the vapouisation of liquid water which is H

2

O(l)→H

2

O(g)

Hence, the heat of vapourisation of liquid water is −241.84+285.77=43.93KJmol

−1

Answer 2

Explanation:

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